Question

Question #93411

Answer 1

I think you mistook 5cal for 5kcal

Explanation:

Using the equation `DeltaQ=mcDeltaT`, we know
`m=100`
`c=4.184`

If we assumed that you meant 5 kilocalories, then `DeltaQ` would be `5*4184=20920` (joules)

`20920=100*4.184*DeltaT`
`DeltaT=50`

Therefore if your initial temperature was 20, the final temperature would be `20+50=70ºC`.