Question #d407c

1 Answer
Jan 15, 2018

The solutions are #S={160.6^@,305.7^@}#. The max. and min. are #=5# and #-5#

Explanation:

#rcos(theta+alpha)=r(costhetacosalpha+sinthetasinalpha)#

#=rcosthetacosalpha+rsinthetasinalpha)#

Comparing this to the equation

#3costheta-4sintheta#

We see that

#rcosalpha=3#,

and

#rsinalpha=-4#

Therefore,

#(rcosalpha)^2+(rsinalpha)^2=r^2#

#r^2=3^2+(-4)^2=9+16=25#

Therefore,

#r=sqrt(25)=5#

#cosalpha=3/5#

and

#sinalpha=-4/5#

#alpha=-53.13^@#, #[mod 2pi]#

The equation is

#3costheta-4sintheta=-1.5#

#5cos(theta-53.13^@)=-1.5#

#cos(theta-53.13^@)=-1.5/5=-0.3#

#theta-53.13^@=107.46^@# and #theta-53.13^@=252.54^@#

#theta=107.46+53.13=160.6^@#

and

#theta=252.54+53.13=305.7^@#

The maximum and minimum values of #(3costheta-4sintheta)# are the max. and min. of #(5cos(theta-53.13^@))# which are

#Max. =5#

#Min. =-5#

graph{3cosx-4sinx [-16.02, 16.01, -8.01, 8.01]}