Question #e82b6

1 Answer
P dilip_k
Jan 20, 2018

#RHS= (secA+1)/(secA-1)#

#= (secA+1)^2/((secA-1)(secA+1))#

#= (secA+1)^2/(sec^2A-1)#

#= (secA+1)^2/tan^2A#

#= ((secA+1)/tanA)^2#

#= (secA/tanA+1/tanA)^2#

#= ((1/cosA)/(sinA/cosA)+1/tanA)^2#

#= (1/sinA+1/tanA)^2#

#=(cosecA+cotA)^2 =LHS#

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