Question #de877

1 Answer
Cem Sentin
Jan 23, 2018

This fraction has removable discontinuity in #x=3#

Explanation:

#x^3+2x^2-11x-12#

=#x^3+x^2+x^2+x-12x-12#

=#x^2*(x+1)+x*(x+1)-12*(x+1)#

=#(x+1)*(x^2+x-12)#

=#(x+1)(x+4)(x-3)# and

#x^2-x-6=(x-3)*(x+2)#

Hence this fraction has removable discontinuity in #x=3#

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