What mass of #"carbon dioxide"# would result after FIERCE heating of a #93.2*g# mass of #"magnesium carbonate"#?

1 Answer
Jan 24, 2018

Approx...#50*g#...

Explanation:

Under FIERCE heat, you could thermally decompose magnesium carbonate...(of course, you COULD add acid to the salt!)..

#MgCO_3(s) + Delta rarr MgO(s) + CO_2(g)uarr#

Now there is a 1:1 molar relationship between the metal carbonate and carbon dioxide...we use #(93.2*g)/(84.31*g*mol^-1)=1.11*mol# with respect to the carbonate...

And given the stoichiometry, we generate 1 equiv carbon dioxide gas...#1.11*molxx44.0*g*mol^-1=48.6*g#, take that atmosphere.

Are you happy with this?

Alternatively, we could treat the carbonate with 2 equiv hydrochloric acid...

#MgCO_3(s) + 2HCl(aq) rarr MgCl_2(g) + H_2O(l) + CO_2(g)uarr#