Question #2fa8b

1 Answer
Jan 25, 2018

mm gm of water of specific heat ss if suffers a temperature change of thetaθ ,then heat(HH) required is m*s*thetamsθ

Given, m = 20 Kgm=20Kg or 20000 gm20000gm
S for water is 1 CGS unit
theta = (95-15) = 80θ=(9515)=80

So, H= 20000*1*80H=20000180 Calorie or 16000001600000 Calorie