# How many atoms of carbon are present in "62.0 g" of this element?

Jan 25, 2018

$3.11 \times {10}^{24}$ atoms.

#### Explanation:

First, you must convert the grams of carbon to moles of carbon. To do this, you must divide the mass $\left(\text{62.0 g}\right)$ by the molecular weight of carbon, which is $\text{12.011 g/mol}$..

$\text{62.0 g"/"12.011 g/mol" = "5.16 moles of carbon}$

Then, convert moles of carbon to atoms of carbon using Avogadro's constant $\left(6.022 \times {10}^{23} \text{ atoms per mole}\right)$

$\text{5.16 moles" xx (6.022 xx 10^23 " atoms")/"1 mole" = 3.11 xx 10^24 " atoms}$