Given a #72.2*g# mass of methane, what is #"(i) the molar quantity"#; #"(ii) the mass of carbon present"#; and #"(iii) the mass of hydrogen present?"#

1 Answer
anor277
Jan 25, 2018

We (i) address the molar quantity...

Explanation:

Well #"moles of stuff"="mass of stuff"/"molar mass of stuff"#

...#"moles of methane"="mass of methane"/"molar mass of methane"#

#(72.2*g)/(16.04*g*mol^-1)=4.50*mol#...and given the formula, this also represents a #4.50*mol# with respect to carbon. And so (ii) we got a MASS of carbon given by the following product...

#4.50*molxx12.011*g*mol^-1=54.1*g#...with respect to carbon.

How many grams with respect to hydrogen?

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