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Answer 1 · 2018-02-03T09:56:57

#x = 46^0#

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Refer figure above.

#given /_1 = 72^0, /_2 = 58^0, /_3 = 2x^0, /_4 = 3x^0#

Sum of the exterior angles of a quadrilateral is always #360^0#

#:. 72 + 58 + 2x + 3x = 360#

#5x = 360 - 72 - 58 = 230#

#x = 230/5 = 46^0#

Four exterior angles are #72^0, 58^0, 92^0, 138^0#

Interior anlge = 180 - Exterior angle.

Four interior angles are #108^0, 122^0, 88^0, 42^0#