# Question f1ab0

${\text{0.422 mol Na"_2"SO}}_{4}$
("60.0 g Na"_2"SO"_4)/(1)*("1 mol Na"_2"SO"_4)/("142.04 g Na"_2"SO"_4) = "0.422 mol Na"_2"SO"_4#
The $\text{142.04 g/mol}$ came from getting the molar mass of ${\text{Na"_2"SO}}_{4}$ from the Periodic table.
Multiply across the top $\left(60 \cdot 1 = 60\right)$ and then divide by the bottom $\left(1 \cdot 142.04 = 142.04\right)$ to get $0.422$ moles.