Question #c738b

1 Answer
Jan 28, 2018

Answer:

#x=4#

Explanation:

Let the number #= x#

Given in the question, we have the expression #x^2# and the expression #4x#

From the question we know that #x^2=4x#

Now we solve like a normal quadratic:

First we factorise

#x^2-4x=0#
#x(x-4)=0#

Now we solve:
#x=0 , x=4#

We know that #x# can't be #0# as #0^2# isn't #= 4*0#

#therefore x=4#

We can check as #4^2 = 4*4#