Question

Question #c65e7

Answer 1

`=44"g/mol"`

Explanation:

1. The condition of the gas is at STP, so that 1 mole of any ideal gas occupies a volume of 22.4L of that ideal gas is the mole relationship where a suitable conversion factor is obtainable from; i.e.,

   `1mol " of any ideal gas"-=22.4L " of any ideal gas"`

2. Given the volume of the gas, convert it to mole. Take note also that `1L=1000mL`. Using the equivalence statements shown above, the value of the gas expressed in mole is;

   `=112cancel(mL)xx(1cancel(L))/(1000cancel(mL))xx(1mol)/(22.4cancel(L))=0.005mol`

3. Now, find the variable `(Mm)` as required in the problem. Plug in values as computed earlier. Thus,

   `eta=(m)/(Mm)`
   where:

   `eta="number of moles"`
   `m=mass`
   `Mm="molar mass"`

`Mm=(m)/(eta)`
`Mm=(0.22g)/(0.005mol`
`Mm=44"g/mol"`