# Question #ff514

${\lim}_{x \to \infty} \frac{31}{e} ^ x = 0$
If the problem is actually ${\lim}_{x \to \infty} \frac{31}{e} ^ x$ then the answer is 0 because the numerator does not grow while the denominator grows without bound, so ${\lim}_{x \to \infty} \frac{31}{e} ^ x = 0$.