Question #12b46

1 Answer
Jan 30, 2018

The speed after #5s# is #=101.1fts^-1#

Explanation:

The forces acting on the body are #mg# acting downwards and #kv# acting upwards.

Therefore,

According to Newton's Second Law

The acceleration is #a=(dv)/dt#

#m(dv)/dt=mg-kv#

Dividing by #m#

#(dv)/dt=g-k/mv#

Let #k/m=b#

Then,

#(dv)/dt=g-bv#

#(dv)/(g-bv)=dt#

Integrating both sides

#int(dv)/(g-bv)=int1*dt#

#-1/bln(|g-bv|)=t+C_1#

#ln(|g-bv|)=-bt-bc_1#

#g-bv=Ce^(-bt)#

Plugging in the initial conditions, #v=0# when #t=0#

#g-0=C*1#, #=>#, #C=g#

Therefore,

#bv=g-g e^(-bt)=g(1-e^(-bt))#

But #b=k/m#

#v=(mg)/k(1-e^(-kt/m))#

Plugging in the limiting speed,

#v_l=lim_(t->+oo)(mg)/k(1-e^(-kt/m))=(mg)/k#

But #v_l=160#

Therefore,

#(mg)/k=160#, #=>#, #m/k=160/g#

Therefore,

#v=160(1-e^(-g/160*t))#

When #t=5s#

The acceleration due to gravity is #g=32fts^-2#

#v(5)=160(1-e^(-32/160*5))=160(1-1/e)=101.1fts^-1#

The speed after #5s# is #=101.1fts^-1#