# How do you graph #3x + y < 4#?

##### 1 Answer

Feb 1, 2018

See a solution process below:

#### Explanation:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

**For:**

**For:**

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

graph{(x^2+(y-4)^2-0.05)((x-2)^2+(y+2)^2-0.05)(3x+y-4)=0 [-10, 10, -5, 5]}

Now, we need to change the boundary line to a dashed line because the inequality operator does not contain an "or equal to" clause. And, we can shade the left side of the line.

graph{(3x+y-4) < 0 [-10, 10, -5, 5]}