What is the molar quantity of an #80*mg# mass of #"propanolol"#, #C_16H_21NO_2#?

1 Answer
anor277
Jan 31, 2018

Well, we add the atomic masses of the constituent elements to get the molar mass..

Explanation:

...and thus we gets...

#{underbrace(16xx12.011+21xx1.00794+14.01+2xx16.00)_"atomic mass of carbon, hydrogen, nitrogen, and oxygen"}*g*mol^-1#

#"Molar mass of propanolol"-=259.35 *g*mol^-1#

And for the molar quantity in a single tablet...we take the quotient..

#(80.0xx10^-3*g)/(259.35*g*mol^-1)=3.08xx10^-4*mol#

And clearly the daily molar dose is #6xx3.08xx10^-4*mol~=2*mmol#

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