Question

What mass of `HCl` is required to react with a `2.78*mol` quantity of magnesium metal?

Answer 1

We interrogate the stoichiometric equation...

`Mg(s) +2HCl(aq) rarr MgCl_2(aq) +H_2(g)uarr`

Explanation:

And given the stoichiometry...a mass with respect to `HCl`...

`2.78*molxx2xx36.46*g*mol^-1~=200*g`

..is consumed...