Question #f10c0

1 Answer
LizZ
Feb 2, 2018

#sqrt(56)/sqrt(7)=2sqrt(2)#

Explanation:

As long as you keep the numbers under the radicals, it's fine to perform multiplication and division with the numbers under the same kind of radical (square roots with square roots, cube roots with cube roots, etc.)
Since #56/7=8#,

#sqrt(56)/sqrt(7)=sqrt(8)#

Simplify #sqrt (8)# by breaking it into factors:
#sqrt (8)=sqrt(4*2)#. Since #sqrt(4)=2#, we can pull #2# out of the radical and rewrite #sqrt (8)# as #2sqrt(2)#

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