Question

Question #16cfd

Answer 1

`Q=ul?J`

Explanation:

1. This can be solved using the standard formula shown below.

   `Q=mCpDeltaT`
   `where:`

   `Q="heat"=ul?`
   `m="mass"=3.3kg`
   `Cp="heat capacity"=(0.128J)/(g*^oC)`
   `DeltaT=T_f-T_i=67^oC-25^oC="change in temperature(final/initial)"`

2. Check units for uniformity. This case, the mass of gold bar is expressed in `kg`; so that, this value must be converted to `g` to match the derived units of the `Cp` value of the material . Note that `1kg=1000g`; the equivalence statement, where a conversion factor is obtainable from; i.e.,

   `m=3.3cancel(kg)xx(1000g)/(1cancel(kg))`
   `m=3,300g`

3. Now, plug in given values to the formula as shown in #"step " 1.# Cancel unwanted/cancellable units and make sure the desired unit is attained.

   `Q=mCpDeltaT`
   `Q=mCp(T_f-T_i)`
   `Q=(3,300cancel(g))((0.128J)/cancel((g*^oC)))(67-25)*cancel(^oC)`
   `Q=ul?J`