Question

Question #5d847

Answer 1

Sum of opposite angles of a cyclic quadrilateral is `180^@`

`/_D+/_B=180=>x+20+3x=180`

`=>x=(180-20)/4=40`

Again

`C+A=180`

`=>C=180-A`

`=>C=180-2x-38`

`=>C=180-2xx40-38=62`