If #2x-7/2+3/2y# and #4x+3y=7#, what are #x# and #y#?

1 Answer
Feb 5, 2018

Provided I have correctly interpreted what was intended:
#color(white)("XXX")(x,y)=(7/4,0)#

Explanation:

Note that in order for the first expression to be an equation, I have replaced the #color(blue)+# in #2x-7/2color(blue)+ -3/2y# with an #color(red)(=)#. (I assumed this was a typo and the #color(blue)+# and the #color(red)=# are typically on the same key).

Given
[1]#color(white)("XXX")2x-7/2color(red)(=)3/2y#
[2]#color(white)("XXX")4x+3y=7#

Rearranging [1] into standard form (#Ax+By=C, ABC in ZZ#)
[3]#color(white)("XXX")4x-3y=7#

Adding [2] and [3] together
[4]#color(white)("XXX")8x=14#
#rArr#[5]#color(white)("XXX")x=7/4#

Subtracting [3] from [2]
[6]#color(white)("XXX")6y=0#
#rArr#[7]#color(white)("XXX")y=0#