Question #82413

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Answer 1 · 2018-02-05T19:17:17

Given #f(x)#, the average rate of change from #x_1 = a# to #x_2 = b# is:

#"Average rate of change"= (f(b)-f(a))/(b-a)#

In this problem, we are given that:

#f(x)=x^2+5x−8#, #x_1 = 2#, and #x_2 = 6#

#"Average rate of change"= (f(6)-f(2))/(6-2)#

#"Average rate of change"= (6^2+5(6)−8-(2^2+5(2)−8))/4#

#"Average rate of change"= 13#

Answer 2 · 2018-02-05T19:21:40

#(f(6)-f(2))/(6-2)=13#

#f(6)=6^2+6.5-8=58#

#f(2)=2^2+2.5-8=6#

#6-2=4#