# Question #05248

##### 1 Answer

Feb 6, 2018

In point-slope form:

In slope intercept form:

#### Explanation:

We'll begin by finding

Given

Then

Next we evaluate the derivative at given

So

So the slope of the tangent line is

Now that we have the slope

So we substitute the known values and we'll get the equation of the tangent line in point-slope form:

In slope intercept form the equation of the tangent line:

Here's a graph of the function along with its tangent line at