Question #65d62

1 Answer
Feb 6, 2018

#(d^2y)/(dx^2)=(3x^(-5/2))/4#

Explanation:

#y=1/sqrt(x)=x^(-1/2)#

#dy/dx=d/dx[x^(-1/2)]#
#color(white)(dy/dx)=-1/2*x^(-1/2-1)#
#color(white)(dy/dx)=-(x^(-3/2))/2#

#dy/dx=-(x^(-3/2))/2#
#(d^2y)/(dx^2)=d/dx[dy/dx]=d/dx[-(x^(-3/2))/2]#
#color(white)((d^2y)/(dx^2))=-3/2*-x^(-3/2-1)/2#
#color(white)((d^2y)/(dx^2))=(3x^(-5/2))/4#