Question

Question #17455

Answer 1

`lim_{x->0} (x+sin3x)/(2x+sin5x) = lim_{x->0} (1+3cos3x)/(2+5cos5x) = 4/7`

Explanation:

Using l'Hopital's rule:
`lim_{x->0} (x+sin3x)/(2x+sin5x) = lim_{x->0} (1+3cos3x)/(2+5cos5x) = 4/7`