Question

Question #95dd5

Answer 1

`LHS=2 sin 2B - 2 cot B`

`-2cotB(1- (sin 2B)/cot B )`

`-2cotB(1- (2sinBcosB*sinB)/cosB )`

`-2cotB(1- 2sin^2B)`

`= -2 cot B cos 2B=RHS`