# Question a3fcc

Feb 6, 2018

#### Answer:

The mass of $4.35 \times {10}^{25}$ ${N}_{2}$ molecules is $2024$ $g$.

#### Explanation:

Nitrogen atoms have a molar mass of $14$ $g m o {l}^{-} 1$.

The ${N}_{2}$ molecule has 2 atoms, so it has twice that mass, $28$ $g m o {l}^{-} 1$.

That means that one mole, Avogadro's number, $6.02 \times {10}^{3}$, of ${N}_{2}$ molecules would have a mass of $28$g.

To find our answer, then, we calculate:

$\frac{4.35 \times {10}^{25}}{6.02 \times {10}^{23}} \times 28 = 2024$ $g$