Question #8969e

1 Answer
Samikshya Thatal · Nam D.
Feb 7, 2018

Please refer to the explanation.

Explanation:

We know,

#Sin(A+B)=SinACosB + CosA SinB#

so if,

#Sin (A+A)=SinA CosA + CosA SinA#

#Sin2A = SinA CosA + SinA CosA#

Therefore, #Sin2A = 2SinA CosA#

so we go here,

#LHS =1/sin(x+x)#

#=1/(sinx cosx +cosx sinx)#

#=1/2sinx cosx#

#=RHS#

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