Question #5e126

1 Answer
Feb 8, 2018

0.9139 liters

Explanation:

Mass of #C_6H_12O_6 = 72 + 12 + 64 = 148 gmol^-1#

Mole of glucose #rArr (1g)/(148gmol^-1) = 0.0068mol# of Glucose

Mole ratio between glucose and water is #1:6#

Then; water is #0.0068 xx 6 = 0.0408 mol# of water

Volume of water is #0.0408mol xx (22.4 L)/(1mol) = 0.9139 L#