Question #b834f

1 Answer
P dilip_k
Feb 8, 2018

#LHS=(sin x - cos x + 1)/( sin x+ cos x -1)#
#=(cosx(sin x - cos x + 1))/( cosx(sin x+ cos x -1))#
#=(cosx(sin x - cos x + 1))/( cos ^2x -cosx(1-sinx))#

#=(cosx(sin x - cos x + 1))/( (1- sin^2x )-cosx(1-sinx))#
#=(cosx(sin x - cos x + 1))/( (1- sinx )(1+sinx-cosx))#
#=cosx/( 1- sinx )#

#=(cosx/cosx)/(( 1- sinx )/cosx)#

# = 1/ (secx - tan x)=RHS#

Related questions
Impact of this question
245 views around the world
You can reuse this answer
Creative Commons License