What is the general solution of the differential equation? : # dy/dx = 1/x^2 #

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Answer 1 · 2018-02-07T18:03:56

# y =-1/x + C #

We have:

# dy/dx = 1/x^2 #

This is a First Order Separable Ordinary Differential Equation. We can "separate the variables" to get:

# int \ dy = int \ 1/x^2 \ dx #

Both integrals are standard calculus results , so integrating we get:

# y = x^(-1)/(-1) + C #
# \ \ = -1/x + C #

Which is the General Solution