Question #9b941

1 Answer
Feb 11, 2018

#x^3+4x^2-41x-36=0#

Explanation:

Given:
zeroes of the polynomial are 1,-9 and4
#x=1# is a root of the polynomial
#x=-9# is a root of the polynomial
#x=4# is a root of the polynomial

That means
#x-1=0, x+9=0, x-4=0# form the ;inear combination
#(x-1)(x+9)(x-4)=0# happens to be the factored equation
Expanding this product of three terms
#x^3+(-1+9-4)x^2+((-1)(9)+(9)(-4)+(-4)(-1))x+(-1)(-9)(-4)=0#
#x^3+4x^2-41x-36=0#