# Question #59f8a

Feb 14, 2018

Yes to both parts.

#### Explanation:

I think this question is supposed to help you explore the concepts included. There's no one right way to do it.

I drew a picture of a cube and a picture of a long, skinny, rectangular prism.

If the cube is $2$in. x $2$in. x $2$in., it's surface area is $6 \cdot 2$in${.}^{2} = 12$in${.}^{2}$
Its volume is $8$in${.}^{3}$

If the prism is $7$in. x $1$in. x $1$in., its surface area is $\left(2 \left(1\right) + 4 \left(7\right)\right)$in${.}^{2}$ or $\left(2 + 28\right)$in${.}^{2}$= $30$in${.}^{2}$

The volume of the thin prism is just $1$ x $1$ x $7$in${.}^{3}$,
or $7$in${.}^{3}$

The volume of the second figure is much smaller than that of the first, but its surface area is obviously larger.

Second question: A box with the measurements $2$ in. x $4$in. x$3$in. has a volume of $24$ in${.}^{3}$, as does a box that is
$6$ in. x $1$ in. x $4$ in.