Question

Question #32022

Answer 1

`3^3/2^4`

Explanation:

`lim_( x → 0) (sin^4 2x)/(xsin^3 3x) = lim_(x->0)(2^4/3^3)(3^3x^4)/( 2^4x^4) (sin^4 2x)/(xsin^3 3x) = lim_(x->0)(3^3/2^4)((sin2x)/(2x))^4((3x)/(sin 3x))^3 = 3^3/2^4`