What mass of salt would result from the reaction between the alkali metal, and #10*mol# #"chlorine gas"#?

1 Answer
Feb 20, 2018

Answer:

Just under #1200*g# of salt would result....

Explanation:

We write the stoichiometric equation...

#Na(s)+1/2Cl_2(g) rarr NaCl(s)#

And so with respect to each equiv of dichlorine gas we GETS 2 equiv of salt...and since we used #10*mol# #Cl_2# we get approx. #20*mol# salt...

Thus #20*molxx58.44*g*mol^-1=??*g#...