5sinx=5sqrt(3)cosx 0<x<2pi What are all possible solutions in radians?

1 Answer
Shiva Prakash M V
Mar 2, 2018

valid for
#theta=pi/3,pi+(pi/3)#

Explanation:

Given:
#5sinx=5sqrt3cosx#

#5sinx/cosx=(5sqrt3)cosx/cosx#

#sinx/cosx-=tanx#

#tanx=sqrt3#

#tan(pi/3)=sqrt3#

tan is positive in first and third quadrant
valid for
#theta=pi/3,pi+(pi/3)#

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