Question

800g.flask of water is heated from 20'C to 85'C, how much heat (in joules) did the water absorb?

Answer 1

`217672` joules

Explanation:

We use the specific heat equation, which states that,

`q=mcDeltaT`

• `m` is the mass of the substance

• `c` is the specific heat capacity of the substance

• `DeltaT` is the change in temperature

The specific heat of water is `c=(4.186 \ "J")/("g" \ ""^@"C")`.

Here, `DeltaT=85^@"C"-20^@"C"=65^@"C"`.

So, we get,

`q=800color(red)cancelcolor(black)"g"*(4.186 \ "J")/(color(red)cancelcolor(black)"g"color(red)cancelcolor(black)(""^@"C"))*65color(red)cancelcolor(black)(""^@"C")`

`=217672 \ "J"`