Question

96 g of methane gas, CH4, are placed under a pressure of 3.00atm at 36C. How many liters does the gas occupy?

Don't know how to exactly get the volume of liters

Answer 1

`50.7" L"`

Explanation:

To apply
`PV=nRT`
We need the mols of methane

`96 "g" CH_4*(1 "mol CH"_4)/(16 "g CH"_4)= 6 "mol CH"_4`

Apply `PV=nRT` and solve for V:

`V=(nRT)/P`

Use temp in Kelvin:

`V=(6 mol*0.0821 (Latm)/(molK)*309 K)/(3 atm)= 50.7" L"`