A #"0.4596 g"# sample of a pure soluble chloride compound is dissolved in water, and all of the chloride ion is precipitated as #"AgCl"# by the addition of an excess of silver nitrate. The mass of the resulting #"AgCl"# is found to be #"0.6326 g"#...?
Good question......we first determine the mass of chloride present, we gots.....
Note that it would not be terribly practical to use silver chloride gravimetrically; it would tend to photo-oxidize, and at any rate it is a very curdy material that would be hard to isolate.......
Now here, chloride anion was the material in deficiency; i.e. silver ion was present in excess.....there was thus a mass of