# A 0.67 L solution of ammonium sulfate, (NH_4)_2SO_4 contains 0.81 mole of the solute. What is the approximate molarity of the solution?

May 29, 2016

Approximately 1.21 M

#### Explanation:

If you look up the formula for molarity, you will find this:

$M o l a r i t y = \frac{m o l}{l i t e r s}$

or

$M = \frac{n}{V}$

So you are given :

V = 0.67 L
n = 0.81 mol

Plug in these numbers in the formula:

$M = \frac{0.81}{0.67}$

Molarity = 1.21 M