A 0.67 L solution of ammonium sulfate, #(NH_4)_2SO_4# contains 0.81 mole of the solute. What is the approximate molarity of the solution?

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Answer 1 · 2016-05-29T19:31:38

Approximately 1.21 M

If you look up the formula for molarity, you will find this:

#Molarity = (mol) / (liters)#

or

#M = n/V#

So you are given :

V = 0.67 L
n = 0.81 mol

Plug in these numbers in the formula:

#M = 0.81 / 0.67#

Molarity = 1.21 M