A .0250 kg sock spins in a dryer of radius .225 m once every .304 seconds. How much centripetal force acts on the sock?

2 Answers
Sep 30, 2017

24.025N

Explanation:

Fcentripital=mv2r
m=0.250kg
r=0.225m

v=?
v=distancetime

Here, distance =2πr

v=(2π0.225)m(0.304)s=4.65ms

Now, substituting,
Fcentripital=0.25kg(4.65ms)20.225m

With a little help from Google,😁

Fcentripital=24.025N

Sep 30, 2017

The force is found from F =mv2r or more simply in this case F =mω2r

Explanation:

You calculate ω from 2π.f

Should work out ok.