# A={1,2,3,4,5,6};How many bijective functions f:A->Ahave the property that f(1)!=2?

##### 1 Answer
Mar 26, 2017

$600$

#### Explanation:

A bijective function from a finite set to itself is a permutation.

There are a total of 6! permutations of $6$ objects, of which exactly $\frac{1}{6}$ map $1$ to $2$.

So the answer is:

6!*(5/6) = 5!*5 = 120*5 = 600