Question

A 1.25 kg weight is hung from a vertical spring. The spring stretches by 3.75 cm from its original, unstretched length. How much mass should you hang from the spring so it will stretch by 8.13 cm?

Answer 1

Remember Hookes law.
2.71Kg

Explanation:

Hooke's Law relates Force a spring exerts to an object attached to it as:

`F= -k*x`
where F is the force, k a spring constant, and x the distance it will stretch

So in your case, the spring constant evaluates to:

`1.25/3.75 = 0.333` kg/cm

To get an 8.13cm extension you would need: `0.333 * 8.13`
2.71Kg