# A 10 kilogram object falls freely for a distance of 6.0 meters near Earth's surface. What is the total kinetic energy gained by the object as it falls?

$t = \sqrt{2 \frac{s}{g}} = 1.106 s$
then you find the final speed of the object $v = a t = 10.85 \frac{m}{s}$
and consider the formula $\mathrm{dK} = \frac{1}{2} m {v}^{2} = 588.6 J$