Question

A 10 kL weather balloon containing He at 25 C drops onto an ice field at - 25 what would its volume be if the the pressure remains constant?

Answer 1

Using Charles Law, the answer is about 8.33kL

Explanation:

Charles law states that `V/T = V/T`

The first status of the baloon is where the baloon has a volume of 10 kL, and 25 C, or 298 Kelvin

The second condition only gives temperature, -25 C, i presume, or 248 Kelvin.

Using Charles Law, we can determine

`(10kL)/(298K) = (x kL )/ (248K)`

Simply solve for `x`