A 16 kg is accelerated from 5 m/s to 17 m/s in 4.0 seconds for a distance of of 3.0 m. How much work was done?

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Answer 1 · 2018-03-17T15:31:39

Work done by a force is expressed as #W=F*s=ma=(m(v-u))/t *s =(16(17-5))/4 *3=144J#