# A 2.3 x 10^-4 M solution has trasmittance of 0.508 when placed in a cell of path length 1 cm at wavelength 525 nm. Calculate the absorbance if concentration is doubled?

The absorbance should be $1.160$, or thereabouts.
The $\text{Beer Lambert Law}$, holds that $A = \epsilon b C$, where $\epsilon = \text{molar absorptivity}$; $b = {\text{cell path length"; and c="concentration in mol L}}^{-} 1$.
So if we double the concentration, (or double the path length), we should in principle, double the absorbance. In practice, it is never this easy to do and deviations are common. The $\text{Beer Lambert Law}$ only approximately holds at low concentrations, $\cong 0.1 \cdot m o l \cdot {L}^{-} 1$ or lower.