Question

A 2.6kg car is rolling down a frictionless incline that makes an angle of 23º to the horizontal. The initial speed of the car is 4.3m/s. What is the speed of the car 26m down the incline?

Answer 1

`v = 14.8 m/s`

Explanation:

The car's acceleration down the slope, `a_"ds"`, will be

`a_"ds" = g*sin23^@ = 3.83 m/s^2`

Using the formula `v^2 = u^2 + 2*a*d`,

`v^2 = (4.3 m/s)^2 + 2*3.83 m/s^2*26 m = 217.6 m^2/s^2`

`v = sqrt(217.6 m^2/s^2) = 14.8 m/s`

I hope this helps,
Steve