# A 20.0-g sample of sugar is dissolved in 59.8 g water. What is the concentration of the solution?

Approx. $1.9 \cdot m o l \cdot {L}^{-} 1$ with respect to glucose........${C}_{6} {H}_{12} {O}_{6}$.....
And thus $\text{Concentration"="Moles of solute"/"Volume of solution.}$
=((20.0*g)/(180.16*g*mol^-1))/((59.8*g)/(1.00*g*mL^-1)xx10^-3*L*mL^-1)=??*mol*L^-1.