Question

A 20.0-g sample of sugar is dissolved in 59.8 g water. What is the concentration of the solution?

Answer 1

Approx. `1.9*mol*L^-1` with respect to glucose........`C_6H_12O_6`.....

Explanation:

With aqueous solutions it is usual to assume that dissolution of the solute occurs with little to NO change in solution volume.

And thus `"Concentration"="Moles of solute"/"Volume of solution."`

`=((20.0*g)/(180.16*g*mol^-1))/((59.8*g)/(1.00*g*mL^-1)xx10^-3*L*mL^-1)=??*mol*L^-1`.