A 25.0 mL sample of sulfuric acid is completely neutralized by 32.8 mL of 0.116 mol/L ammonia solution. Ammonium sulfate is formed What is the concentration of the sulfuric acid?

1 Answer
Dec 19, 2016

Answer:

Approx. #0.08*mol*L^-1# with respect to sulfuric acid.

Explanation:

We need (i) a stroichiometric equation:

#H_2SO_4(aq) + 2NH_3(aq) rarr 2NH_4^+ + SO_4^(2-)#

At the 2nd equivalence point, the solution will stoichiometric in #"ammonium sulfate"#. An appropriate indicator must be used.

And (ii) a calculation,

#[H_2SO_4]=1/2xx(32.8xx10^-3*Lxx0.116*mol*L^-1)/(25.0xx10^-3*L)#

#=??*mol*L^-1#

Why did we use a #1/2# factor in the calculation?